Question Description
I. Given data of a simple curve: Azimuth from south of line AB = 275°, Azimuth from south of line BC 323°, R = 327.4 m, sta PC = 1+073
Find:
1. Sta PT
2. Sta of point 3 on a curve.
3. deflection angle of point 3
4. c2
2. A parabolic curve having a forward tangent of +3.5% intersects a back tangent of -7% at station 10+800 whose elevation is 520m. If the length of the curve is 350m., find the stationing and elevation at the lowest point.
3. Given base = 6.2m, 6.6/+2.4 0/+2.0 x/+1.2
1. Find the side slope
2. Find x
3. Find the cross-sectional area.
Answers
Answered by
0
Answer:
dnsuhabrjsks
nd
Step-by-step explanation:
snakehriskdheuwnevsianrhakdkgns
Similar questions