Question

║⊕QUESTION⊕║
DIG YOUR BRAINS AGAIN !!!!!!!!
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CLASS 11
PERMUTATIONS AND COMBINATIONS
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How many numbers of 6 digits can be formed from the digits 0, 1, 3, 5, 7 and 9, when no digit is repeated?

Answer 1

Answer:

600

Step-by-step explanation:

Hello

As this is The question of Permutation it will take time.

So,

_ _ _ _ _ _

We have total 6 digits and have to form 6 digit no.

To form 6 digit no. it shouldn't start with 0. So, For 1st digit we have 5 choices

Now for other digits it will be 5 choices followed by 4,3,2,1 as no digit is repeated.

So answer is (5×5×4×3×2×1)

=600

Answer 2

Answer:

600 is the answer to your question

Step-by-step explanation:

5×5×4×3×2×1=600

There would be six digits

so

• first digit can be from any of the 5(1,3,5,7,9)numbers out of from 6 numbers(0, 1,3,5,7,9)here we can't take 0 as it will make 5 digit number if we use
• second digit can be now from 5 numbers remaining as one number would be used above
• third digit can be now from 4 numbers remaining
• And like this it will continue