Question

Question:
Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
N2 (g) + H2 (g) → 2NH3 (g)

(i) Calculate the mass of ammonia produced if 2.00 x 10³ g dinitrogen reacts with 1.00 x 10³ g of dihydrogen.
(ii) Will any of the two reactants remain unreacted?
(iii) If yes, which one and what would be its mass?

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Answer 1

Answer:

N2(g) + 3H2(g) →2NH3(g)

28g 6g 34g

28 g of N2 reacts with 6g of H2.

1g of N2 reacts with 6/28 g of H2

2000g of N2 will react with 2000 × 6/28

= 428.57 of H2

but H2 is given 1 × 10³g is greater than 428.57 g

N2 is a limiting reagent and limits the production of ammonia

28g of N2 produces 34 g of NH3

1g of N2 produces 34/28 g of NH3

2000g of N2 will produce 34/28 × 2000

= 2428.57 g of NH3.

(ii) H2 is excess so it remains unreacted

(iii) Mass of unreacted dihydrogen = 1000-428.57

=571.43g