Question

║⊕QUESTION⊕║
Do not worry about your difficulties in Mathematics. I can assure you mine are still greater !!!!!!! XD
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CLASS 11
SEQUENCES AND SERIES
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If there are 76 terms in an A.P. of which the first term is 9 and the last is 384; find the 50th term of the A.P.

Answer 1

Step-by-step explanation:

There are 76 terms

a = t1 = 9

t76 = 384

We know the formula

tn = a +(n-1)d

384 = 9 + 76d -76

384 = 76d - 67

384 +67 = 76d

451 = 76d

d = 5.93 ~ 6

t50 = a +(n-1) d

= 9 + 49×6

= 9 + 294

= 303

hope it helps you!!!!!

Answer 2

Answer:

Step-by-step explanation:

Total terms = 76

a +(n-1)d

384 = 9 + 76d -76

384 = 76d - 67

384 +67 = 76d

451 = 76d

d = 451 / 76

t50 = a +(n-1) d

9 + 49*6

9 + 294

= 303

Answer = 303