Question. Equal weight of me equal weight of Ethane and hydrogen are mixed in an Empty container of 25 degree Celsius the fraction of the total pressure exerted by hydrogen is???
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Answered by
9
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☬ YOUR ANSWER ☬
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Let the x gram gas is mixed
Mole of ethane =
Mole of hydrogen = x/2
mole fraction of hydrogen =
= mole fraction of hydrogen
= 15 : 16
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☬ THANKS! Regards ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
Let the x gram gas is mixed
Mole of ethane =
Mole of hydrogen = x/2
mole fraction of hydrogen =
= mole fraction of hydrogen
= 15 : 16
╒══════════════════════╕
☬ THANKS! Regards ☬
╘══════════════════════╛
Answered by
2
Let x g each of hydrogen and ethane are mixed.
The moles of hydrogen and methane are
x\2
and
x\30
respectively.
The mole fraction of hydrogen is
=x2\x\2+x\30=15\16
The partial pressure of hydrogen is the product of its mole fraction and total pressure.
Thus,
Partial pressure of H2 Total pressure=mole fraction of hydrogen=15\16
Similar questions
The moles of hydrogen and methane are
x\2
and
x\30
respectively.
The mole fraction of hydrogen is
=x2\x\2+x\30=15\16
.
The partial pressure of hydrogen is the product of its mole fraction and total pressure.
Thus
Partial pressure of H2 Total pressure=mole fraction of hydrogen=15\16
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