Question

Question :-

Evaluate the derivative of f(x) = sin2x using Leibnitz product rule.

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Answer 1

✯ Qᴜᴇsᴛɪᴏɴ.

• Evaluate the derivative of f(x) = sin2x using Leibnitz product rule.

✯ Exᴘʟᴀɴᴀᴛɪᴏɴ.

✠ Given Info ➽ f(x) = sin2x

❖ Let ☛ y= sin2x

☩ Then, according to the question,

✢ We have to use Leibnitz product rule,

☩ Then,

➯ dy/dx = (d/dx) sin2x

➯ dy/dx = (d/dx) (sin x)(sin x)

➯ dy/dx = (sin x)’(sin x) + (sin x)(sin x)’

➯ dy/dx = cos x sin x + sin x cos x

➯ dy/dx = 2 sin x cos x

➠ dy/dx = sin2x

❃ Therefore, the answer is sin2x.

✬ Hope it helps u ✬

Answer 2

Answer:

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