Math, asked by aryamanv7, 8 months ago

Question : Factorize: 27a3b3 − 45a4b2 Question : Factorize: 2a(x + y) − 3b(x + y) Question : Factorize :2x(p2 + q2) + 4y(p2 + q2) Question : Factorise : 5 – 20x2 Question :Factorize : 3a3b − 243ab3

Answers

Answered by Anonymous
2

Answer:

1) 27a3b3−45a4b2

=9a3b2(3b−5a)27a3b3-45a4b2

=9a3b2(3b-5a)

2) 2a(x + y) − 3b(x + y)

=(x+y)(2a-3b)

3) 2x(p2 + q2) + 4y(p2 + q2)

=(p2+q2)(2x+4y)

=2(p2+q2)(x+2y)

4) 3a3b-243ab3

=3ab(a²-81b²)

=3ab(a²-(9b)²)

=3ab(a-9b)(a+9b)

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Answered by Anonymous
1

1) 27a3b3−45a4b2

=9a3b2(3b−5a)27a3b3-45a4b2

=9a3b2(3b-5a)

2) 2a(x + y) − 3b(x + y)

=(x+y)(2a-3b)

3) 2x(p2 + q2) + 4y(p2 + q2)

=(p2+q2)(2x+4y)

=2(p2+q2)(x+2y)

4) 3a3b-243ab3

=3ab(a²-81b²)

=3ab(a²-(9b)²)

=3ab(a-9b)(a+9b)

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