Question

QUESTION : ( fig. in attachment )

In the give figure,
angle A = 54°. BO and CO are the bisectors of angle B and angle C.. Find angle BOC.

Hint :
$in \: ∆BOC, 2x + 2y + 54° = 180° \: \\ = 2(x + y) = 126°$
$= x + y = 63°$
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Answer 1

Answer:

$in \: triangle \: abc \: \: 54 + 2x + 2y = 180 \\ 2(x + y) = 180 - 54 \\ x + y = \frac{126}{2} \\ x + y = 63 \\ x + y + z = 180 \\ 63 + z = 180 \\ z = 180 - 63 \\ z = 117$

Answer 2

In Triangle abc :-

54 + 2x + 2y = 180

2 ( x + y ) = 180−54

x + y = 126/2

x + y = 63

x + y + z = 180

63 + z = 18

z = 180−63

z = 117