Question

Question File
A cyclist is taking a turn with speed 30 m/s on a 90 m radius.
g = 10ms -2, angle of bending will be
A 45°
B. 30°
C 60°
D 90°
Answer
OA B C D​

Answer 1

Given:

A cyclist is taking a turn with speed 30 m/s on a 90 m radius and g = 10m/s².

To find:

Angle of bending ?

Calculation:

While travelling on a curved road, cyclist have to bend a certain angle with the vertical such that they are able to take the turn safely.

Let angle of bending be $\theta$.

General expression for bending of a cyclist is given as:

$\therefore \: \tan( \theta) = \dfrac{ {v}^{2} }{rg}$

$\implies\: \tan( \theta) = \dfrac{ {(30)}^{2} }{90 \times 10}$

$\implies\: \tan( \theta) = \dfrac{ 900 }{90 \times 10}$

$\implies\: \tan( \theta) = \dfrac{ 900 }{900}$

$\implies\: \tan( \theta) = 1$

$\implies \: \theta = {45}^{ \circ}$

So, angle of bending is 45°.