Question

question : Find ‘k’ if ( x - 2 ) is a factor of x^3- kx^2- 112 ans: p(x)= x³-kx²-112 g(x)=> x-2=0 =>x =2 p(2) => (2)³-k(2)²-112 =>8-k4-112 => -k4+8-112 =>-k4-104 -k4-104=0 => -k4 = 104 =>-k = 104/4 =>k = -26 is this answer correct? - 26 or + 26 which is correct ? explain it

Answer 1

x-2 is a factor of x³-kx²-112

Therefore, x=2 is zero of x³-kx²-112

Therefore,

p(2)=(2)³-k×(2)²-112=0

=> 8-4k-112=0

=> -4k-104=0

=> -4k=104

$= > k = \frac{104}{ - 4}$

k=-26

k=-26 is right answer

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