Question

question:find the amount and compund interst compounded anually on:Rs.20,000 at 9% p.a for 2 years​....... jise answer dena h plz step ny step krke btaye​

Answer 1

$= 20000 {(1 + \frac{ 9\%}{1} )}^{2 } \\ = 20000{(1 + \frac{ 9}{100} )}^{2} \\ = 20000 {( \frac{209}{100}) }^{2} \\ = \frac{20000 \times 209 \times 209}{100 \times 100} \\ =Rs. 23762$

Answer 2

Answer:

• Amount=>23762

• Compound Interest =>3762

Explanation:

Given :

• Principal (p)=>20000
• Time(t)=> 2 year
• Rate(r)=>9%

To Find :

• Amount and compound interest

Solution :

Amount formula for compounded anually

$\sf{Amount}=p\bigg(1+\dfrac{r}{100}\bigg)^{n}$

Substitute the values :-

$\sf{A}=20000\bigg(1+\dfrac{9}{100}\bigg)^{2}$

$\sf{A}=20000\bigg(\dfrac{11881}{10000}\bigg)$

$\sf{A}=2\times11881$

∴ A = 23762

Compound interest (CI) formula

$\boxed{\sf{CI=Amount - Principal}}$

Substitute the values

Compound Interest  = 23762 - 20000

∴ CI = 3762