Question

question- find the net work done.​

Answer 1

Question :

An ideal gas undergoes cyclic process ABCDA as shown in given P-V diagram. The amount of work done by the gas is..$.$

Solution :

❖ In thermodynamic process, work done is measured as the product of pressure and change in volume.

A] Work - 1 (AB) :

➙ W₁ = (P｡- 2P｡) (V｡- V｡)

➙ W₁ = 0

B] Work - 2 (BC) :

➙ W₂ = P｡(3V｡- V｡)

➙ W₂ = 2P｡V｡

C] Work - 3 (CD) :

➙ W₃ = (2P｡- P｡) (V｡- V｡)

➙ W₃ = 0

D] Work - 4 (DA) :

➙ W₄ = 2P｡(V｡- 3V｡)

➙ W₄ = 2P｡(-2V｡)

➙ W₄ = -4P｡V｡

Net work done;

➠ W = W₁ + W₂ + W₃ + W₄

➠ W = 0 + 2P｡V｡+ 0 - 4P｡V｡

➠ W = -2P｡V｡

Answer 2

$\huge\colorbox{yellow}{Áηѕωєя࿐❤}$

Question :

An ideal gas undergoes cyclic process ABCDA as shown in given P-V diagram. The amount of work done by the gas is....

Solution :

❖ In thermodynamic process, work done is measured as the product of pressure and change in volume.

A] Work - 1 (AB) :

➙ W₁ = (P｡- 2P｡) (V｡- V｡)

➙ W₁ = 0

B] Work - 2 (BC) :

➙ W₂ = P｡(3V｡- V｡)

➙ W₂ = 2P｡V｡

C] Work - 3 (CD) :

➙ W₃ = (2P｡- P｡) (V｡- V｡)

➙ W₃ = 0

D] Work - 4 (DA) :

➙ W₄ = 2P｡(V｡- 3V｡)

➙ W₄ = 2P｡(-2V｡)

➙ W₄ = -4P｡V｡

Net work done;

➠ W = W₁ + W₂ + W₃ + W₄

➠ W = 0 + 2P｡V｡+ 0 - 4P｡V｡

➠ W = -2P｡V｡

Hope it helps :)