Math, asked by sandhyapm2004, 10 months ago

QUESTION:
Find the number of bricks, each measuring 25 cm ×12.5 cm×7.5 cm, required to construct a wall 24m long, 20m high and 0.5 m thick ,while the cement and the sand mixture occupies 1/20 th of the volume of the wall.​

Answers

Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
2

Answer:

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Volume of wall=500×600×5=15000000 volume of mixture=15000000×1/20=750000 left wall volume =15000000_750000=14250000 required brick=14250000/25×12.5×7

5=6080

Answered by Anonymous
5

\huge\star\mathfrak\blue{{Answer:-}}

Bricks Wall

l=25 cm l=6 m =600 cm

b=12.5 cm b=50 cm

h=7.5 cm h=5 m =500 cm

volume of wall=l x b x h

=600 x 50 x 500

=15000000 cubic cm

volume of mixture =1/20 x 15000000

=750000 cubic cm

volume left =15000000 - 750000

=14250000 cubic cm

required brick =14250000/25 x 12.5 x 7.5

=6080 bricks

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