Math, asked by japan29, 11 months ago

Question
Find the sum of all the non-negative terms
of the following sequence: 100, 97, 94, ....​

Answers

Answered by Anonymous
6

Step-by-step explanation:

All are in A.P

we know this as

common difference is same !

Given:

a = t1 = 100

t2 = 97

d = 97-100 = -3

tn = 1

it is zero because question want sum of non - negative terms

so it will not go beyond zero

tn = a +(n-1)d

1= 100 + -3n +3

-102 = -3n

n = 34

Sn = n/2 [ 2a +(n-1) d]

= 34/2 [200 + 33 × (-3) ]

= 34/2 [ 200-99]

= 34 × 51 ..........(50.5~ 51)

= 1734

Hope it helps uh!

Answered by jaikesavaa
2

Answer:

1734

Step-by-step explanation:

All are in A.P

we know this as

common difference is same !

Given:

a = t1 = 100

t2 = 97

d = 97-100 = -3

tn = 1

it is zero because question want sum of non - negative terms

so it will not go beyond zero

tn = a +(n-1)d

1= 100 + -3n +3

-102 = -3n

n = 34

Sn = n/2 [ 2a +(n-1) d]

= 34/2 [200 + 33 × (-3) ]

= 34/2 [ 200-99]

= 34 × 51 ..........(50.5~ 51)

= 1734

Hope it helps u

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