Question

Question!

find the surface area of a cylinder with a height of 40 inches and a base diameter of 12 inches.

Spammers not allowed!​

Answer 1

Given :

• Height of Cylinder = 40inch
• Diameter of Cylinder = 12inch

To Find :

• Find the total surface area of cylinder ?

Solution :

Radius of the cylinder :

➣ Diameter = 2 × Radius

➣ 12 = 2 × Radius

➣ 12/2 = Radius

➣ 6 inch = Radius

Total surface Area of cylinder :

➣ TSA of cylinder = 2πr(h + r)

➣ TSA of cylinder = 2π × 6(40 + 6)

➣ TSA of cylinder = 2π × 6 × 46

➣ TSA of cylinder = 2π × 276

➣ TSA of cylinder = 2 × 22/7 × 276

➣ TSA of cylinder = 44/7 × 276

➣ TSA of cylinder = 44 × 276/7

➣ TSA of cylinder = 12144/7

➣ TSA of cylinder = 1734.85inches

Hence,

• TSA of cylinder is 1734.85inches.

Answer 2

$\: \: \: \: \: \: \: \huge\color {pink}\boxed{\colorbox{black} {❥Answer}}$

$\sf \: A = 2\pi \frac{d}{2} h + 2\pi \binom{d}{2}^{2}$

$\sf \: = 2 \times \pi \times \frac{12}{2} \times 40 + 2 \times \pi \times \binom{12}{2}^{2}$

$\sf \ ≈ \: 1734.15914 {in}^{2}$

$\sf \: ANSWER \rightarrow \: \:T.S.A \: = 1734.16 {in}^{2}$