Math, asked by llToxicQueenll, 8 hours ago


QUESTION ❓

Find the value of p(y) = 2y³ - 2y + √7 for y = -2

Answers

Answered by Anonymous
18

 \huge \rm \underline \red{Answer}

p (y) = 2y³ - 2y + √7

 \thereforep (-2) = 2 × (-2) -2 × (-2) +√7

= 2 × (-8) -2 × (-2) + √7

= -16 + 4 + √7

= -12 + √7

 \thereforeFor y = -2 the value of polynomial is -12 + √7.

Answered by Queen3718
2

p (y) = 2y³ - 2y + √7

\therefore∴ p (-2) = 2 × (-2) -2 × (-2) +√7

= 2 × (-8) -2 × (-2) + √7

= -16 + 4 + √7

= -12 + √7

\therefore∴ For y = -2 the value of polynomial is -12 + √7.

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