Question

Question = Find the Zeros and verify the relationship between Zeros and coefficient.

4u^2+8u

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Answer 1

Question

$4u^{2} \: + 8u$

Solution

To Find Zereos:

p(u) = 0

$p(u) = 4u^{2} + 8u = 0 \\ \\ = 4u \: (u + 2) = 0 \\ \\ = 4u = 0 \: \: \\ \\ = \: u + 2 \: = 0$

4u = 0

u = 0

u + 2 = 0

u = -2

Zereos of p(u) are o and -2

To Verify the relationship

Sum of zereos = -2 + 0 = -2

Product of zereos = -2 × 0 = 0

Sum of zereos =

$\frac{ - coefficient \: of \: u \: }{coefficient \: of \: {u}^{2} } \\ \\ = \frac{ - 8}{4 \:} = \: - 2$

Product of zereos =

$\frac{constant \: term \: }{coefficient \: of \: {x}^{2} } \\ \\ = \: \frac{0}{4} = 0$

Hence, verified

Answer 2

Answer:

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