Question

Question :-
Find two numbers such that one of them exceeds the other by 18 and their sum is 92.​

Answer 1

Let the number is x

The other number is x + 18

$\small\underline\mathrm\purple {According \: to \: the \: given \: question }$

$\sf \: x + x + 18 = 92$

$\sf2x + 18 = 92$

$\sf2x = 92 - 18$

$\sf2x = 74$

$\tt \: x = 74/2$

x = 37 .

Hence :-

The First Number = 37.

The Other Number = x + 18 = 37 + 18 = 55 .

Check :-

37 + 55 = 92 .

Hence :

$\sf\bold{First \: Number \: = \: 37}$

$\sf\bold{Second \: Number \: = \: 55}$

Answer 2

Answer:

37.5 and 55.5

Step-by-step explanation:

let's take the first number as x

it is given that one number exceeds the other by 18

so the other number is x+18

let's form the equation,

x+x+18=93

2x+18=93

2x=93-18

2x=75

x=75/2

x=37.5

so x=37.5

Therefore the first number is 37.5

nd the second number which is x+18

=37.5+18

=55.5

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