Question

QUESTION:------ find X and Y. Is the ∆ABC isosceles? If so,name it's equal sides.
$(tex) \huge \mathfrak \purple {solve \: fast}$
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Answer 1

$\huge\mathfrak\blue{Hey!!}$

SOLUTION:-

Answer:-

→x= 70°

and

→y= 55°

Step-by-Step explanation:-

To solve this question, all you need to do is to extend a line from both the sides from the angle A keeping it || to line CX. [Name the line formed as WAD]. Also, name the transversal formed from the line CX as AY. [Refer the attachment provided above].

Now,

To find angle x°→

110° + x° = 180° [Linear pair axiom]

=> x°= 180°-110°

=>x° = 70°

Now,

angle WAY = 70° [Alternate angle of angle AYC ]

Also,

angle WAY + angle YAC + angle CAD = 180° [Linear pair axiom]....→(i)

Also,

angle YAD= 110° [Exterior alternate angles of angle XYA]

And, as we can see Line AC bisects angle A, therefore, angle YAC and angle CAD will be 55°s each.

Now, on substituting the known values in the linear pair of equation (i), we get,

70° + 55° + 55° = 180°

and,

angle y° = 55° [Alternate angle of angle DAC]

⏩ AND NOW, WE CAN CONCLUDE THAT ∆ AYC is an ISOSCELES TRIANGLE SINCE TWO OF IT'S ANGLES ARE EQUAL IN MEASURE- 55° [Namely, angles YAC and YCA]

$\huge\mathfrak\blue{Hope..it..helps!}$

Answer 2

Answer:

hi deepika Kya kar rahi ho