Question: Find zeroes of the following polynomials: 1) p(x) = 5x - 3 2) p(x) = x^2 - 2x - 8
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Answer:
Let p(x)=x
2
−2x−8
Zero of polunominal is value of x where P (x)=0
Putting p(x)=0
x
2
−2x−8=0
We find roots using splitting the middle e term method
] Here, we need two term where sum=−2 product =−8×1=−8
x
2
−4x+2x−8=0
x(x−4)+2(x−4)=0
(x+2)(x−4)
So x=−2,4
Therefore , α=−2 & β=4 or zero of polunominal
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