Question

Question for 100 point.

A man standing on a desk of a ship which is 10m above water level. he observe the Angle of elevation of the top of the hill is 60° and angle of depression of the base is 30°. Calculate the distance of the hill from the ship and height of the hill.

Answer 1

______Heyy Buddy ❤_____

_____Here's your Answer ____

Given;

EAD = 60° and ACB = 30°.

DE = h.

Now,

In Triangle AED,

tan 60° = DE / EA

$= > \sqrt{3} = h \div x$

$= > h = \sqrt{3} x$


In Triangle ABC,

tan 30° = AB / BC


$= > 1 \div \sqrt{3} = 10 \div x$

$= > \: x = 10 \sqrt{3}$

$putting \: x = 10 \sqrt{3} \: in \: eq.1$

$= > h = \sqrt{3} \times 10 \sqrt{3}$

=> h = 30m

=> DE = h = 30m.

Now,

CD = CE + ED

=> CD = 40 m.

Therefore,

Distance from the ship to the hill is 10 root3 m .

and Height is 40m.

✔✔✔

Answer 2

$<b>$Hey!

Answer is in the attachment.