Math, asked by AbhayT, 11 months ago

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By how much must the sum of
3a  ^{3} b ^{2}  + 2 {a}^{2} b ^{3}  + 6 {a}^{3} b ^{3}
and
a  ^{3} b ^{2}  + 3{a}^{2} b ^{3}   -   {a}^{3} b ^{3}
be increased to get
5a  ^{3} b ^{2}  + 2 {a}^{2} b ^{3}  + 8{a}^{3} b ^{3}

Answers

Answered by khushigupta34
1

Answer:

a³b²-3a²b³+3a³b³

Step-by-step explanation:

5a³b²+2a²b³+8a³b³-(3a³b²+2a²b³+6a³b³+a³b²+3a²b³-a³b³)

5a³b²+2a²b³+8a³b³-3a³b²-2a²b³-6a³b³-a³b²-3a²b³+a³b³

a³b²-3a²b³+3a³b³

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Answered by chanchal12345
2

Answer:

 {a}^{3}  {b}^{2}  \:  - 3 {a}^{2}  {b}^{3}  + 3 {a}^{3}  {b}^{3}

answer is in the attachment

Step-by-step explanation:

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Attachments:
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