Math, asked by amritanshu6563, 9 months ago

Question for Brainly Teachers​

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Answered by IamIronMan0
2

Answer:

Let

 \theta +  \phi = x \:  \\  \theta  -   \phi =y \\  2 \theta  = x + y \:  \: and \:  \: 2 \phi = x - y

It looks easy now

Open the determinate according row 3

 \sin(x + y) ( \sin(x)  \sin(y)   +   \cos(x)  \cos(y) )  \\ +  \sin(x - y) ( \cos(x)  \cos(y)  -  \sin(x)  \sin(y) ) \\  \\  =  \sin(x + y)  \cos(x   - y)  +  \sin(x - y)  \cos(x + y)  \\  \\  =  \sin(x + y + x - y)  \\  \\  =  \sin(2x)  \\  \\  =  \sin(2( \theta +  \phi))

Answered by llBestFriendsll
1

Let

$$\begin{lgathered}\theta + \phi = x \: \\ \theta - \phi =y \\ 2 \theta = x + y \: \: and \: \: 2 \phi = x - y\end{lgathered}$$

It looks easy now

Open the determinate according row 3

$$\begin{lgathered}\sin(x + y) ( \sin(x) \sin(y) + \cos(x) \cos(y) ) \\ + \sin(x - y) ( \cos(x) \cos(y) - \sin(x) \sin(y) ) \\ \\ = \sin(x + y) \cos(x - y) + \sin(x - y) \cos(x + y) \\ \\ = \sin(x + y + x - y) \\ \\ = \sin(2x) \\ \\ = \sin(2( \theta + \phi))\end{lgathered}$$

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