Question

Question for Brainly Teachers​

Answer 1

Step-by-step explanation:

$\left|\begin{array}{ccc} 43&1&3\\35&7&2\\17&3&1\end{array}\right|=0$

C2->C2-14C3

$\left|\begin{array}{ccc} 43-42&1&3\\35-28&7&2\\17-14&3&1\end{array}\right|=0$

$\left|\begin{array}{ccc} 1&1&3\\7&7&2\\3&3&1\end{array}\right|=0$

Here C1 =C3

according to property of Determinant ;if two rows and two columns are identical than Determinant will be zero

so

$\left|\begin{array}{ccc} 1&1&3\\7&7&2\\3&3&1\end{array}\right|=0$

Hope it helps you.

Answer 2

Answer:

Multiply Column 3 by 7 and subtract from 1st .

Operation : C1 -> C1 - 7C2

You get 43-7×6 = 1 , 35 - 7×4 =7 and 17 - 7×2 = 3

in first column which is exactly second column so

determinate will be zero .