Question

question for genius rank​

Answer 1

8Ω

Given: R1 = R2 = R3 = R4 = R5 = 3Ω

In circuit, R2 and R3 are connected in series,

∴ Rs1 = R2 = R3 = 3 + 3 = 6Ω

Rs1 and R4 are in parallel

1/Rp = 1/Rs1 + 1/R4 = 1/6 + 1/3 = 1/2

∴ Rp = 2Ω

Now, R1, Rp and R5 are in series so equivalent resistance of the circuit is

Rs = R1 = Rp = R5

= 3 + 2 + 3 = 8Ω