question for genius rank
Answers
Answer:
Given :
Dimensions of the cuboidal solid block = 30 cm × 40 cm × 50cm.
and
Force applied by block = 50 N
We have to find :
The maximum pressure that will be exerted by the block on ground.
Solution :
Dimensions of the cuboidal solid block
= 30 cm × 40 cm × 50cm.
= 0.3 m × 0.4 m × 0.5 m. [ in meter ]
Now,
֎ Area of the first face =
= 0.3 × 0.4 = 0.12 m²
֎ Area of the second face =
= 0.4 × 0.5 = 0.20 m²
֎ Area of the third face =
= 0.5 × 0.3 = 0.15 m²
Here we can see that, out of the above three faces , is minimum.
Here, we consider the minimum value of area to calculate the maximum pressure because
we know that,
The relation between Pressure (P) , Force(F) and Area (A) is given by ,
∴ The maximum pressure applied by the given cuboidal solid block is 416.6 N/m².
Explanation:
Answer:
Given :
Dimensions of the cuboidal solid block = 30 cm × 40 cm × 50cm.
and
Force applied by block = 50 N
We have to find :
The maximum pressure that will be exerted by the block on ground.
Solution :
Dimensions of the cuboidal solid block
= 30 cm × 40 cm × 50cm.
= 0.3 m × 0.4 m × 0.5 m. [ in meter ]
Now,
֎ Area of the first face =
A1A_1A
1
= 0.3 × 0.4 = 0.12 m²
֎ Area of the second face =
A2A_2A
2
= 0.4 × 0.5 = 0.20 m²
֎ Area of the third face =
A3A_3A
3
= 0.5 × 0.3 = 0.15 m²
Here we can see that, out of the above three faces , A1A_1A
1
is minimum.
Here, we consider the minimum value of area to calculate the maximum pressure because
we know that,
P∝1A\begin{lgathered}P ∝ \frac{1}{A} \\\end{lgathered}
P∝
A
1
The relation between Pressure (P) , Force(F) and Area (A) is given
∴ The maximum pressure applied by the given cuboidal solid block is 416.6 N/m².