Environmental Sciences, asked by shivasinghmohan629, 7 hours ago

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Answers

Answered by studylover41
0

Explanation:

If the force applied by a cuboidal solid block of dimensions 30cm*40cm* 50cm on the ground is 50 N,then the maximum pressure will be exerted on the ground by the face having dimensions and the pressure will be

Thrust due to wooden block,

Mg=5kg×9.8ms

−2

=49N

(a) Surface area of 20cm×10cm surface,

A=(20×10)cm

2

=(0.2×0.1)m

2

=0.02m

2

P=

A

mg

P=

0.02m

2

49N

=

0.02

49

Nm

−2

or Pressure, P=2450Nm

−2

.

(b) Surface area of 40cm×20cm surface,

A=(40×20)cm

2

=(0.4×0.2)m

2

=0.08m

2

P=

0.08m

2

49N

=

0.08

49

Nm

−2

or Pressure, P=612.5Nm

−2

.

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