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Explanation:
If the force applied by a cuboidal solid block of dimensions 30cm*40cm* 50cm on the ground is 50 N,then the maximum pressure will be exerted on the ground by the face having dimensions and the pressure will be
Thrust due to wooden block,
Mg=5kg×9.8ms
−2
=49N
(a) Surface area of 20cm×10cm surface,
A=(20×10)cm
2
=(0.2×0.1)m
2
=0.02m
2
P=
A
mg
P=
0.02m
2
49N
=
0.02
49
Nm
−2
or Pressure, P=2450Nm
−2
.
(b) Surface area of 40cm×20cm surface,
A=(40×20)cm
2
=(0.4×0.2)m
2
=0.08m
2
P=
0.08m
2
49N
=
0.08
49
Nm
−2
or Pressure, P=612.5Nm
−2
.
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