Question

QUESTION :
For Mods and Stars ~

QUESTION :

1. For what value of k, (–4) is a zero of the polynomial x2 – x – (2k + 2) ?

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Answer 1

Yeah Sure I'll help u

For (-4) to be the zero of the polynomial

If we substitute -4 in place of x we must get 0

Therefore

x²-x-(2k+2)= 0 when x= -4

16+4-(2k+2)=0

2k+2= 20

k= 9..

Hope this will help you.

Answer 2

☞Solution :-

$p(x) = {x}^{2} - x - (2k + 2)$

$= p( - 4) = { - 4}^{2} - ( - 4) - (2k + 2)$

$= 16 + 4 - 2k - 2 = 0$

$= 20 - 2k - 2 = 0$

$= 20 - 2 - 2k = 0$

$= 18 - 2k = 0$

$= 18 = 2k$

$= k = \frac{18}{2}$

$k = 9$

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Hopes, it's helpful to you bro. ^_^