Physics, asked by SumanaShree, 6 months ago

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Answered by AssasianCreed
10

Answer :-

Given :-

  • Mass = Mkg

  • V = 5m/sec

  • R = 5m

  • g = 10m/ \sf {sec}^{2}

Solution :-

Block can leave surface of hemisphere if there is no reaction force and Radical acceleration   \sf\bigg( \dfrac{ {V}^{2} }{R}  \bigg) is acted.

Now ,

 \large \boxed   { \bf Formula \:  used}

  \large \boxed { \bf mg \cos( \theta )  =  \frac{ {mv}^{2} }{R} }

 \\  \\  \large \bf \implies \cos( \theta)  =  \dfrac{ {V}^{2} }{g \times  R}

 \\  \\  \large \bf \implies \cos( \theta)  =  \dfrac{ {5}^{2} }{10 \times 5}

 \\  \\  \large \bf \implies \cos \theta =  \dfrac{ \cancel{25}}{ \cancel{50}}

 \\  \\  \large \bf \implies \cos \theta  = \dfrac{1}{2}

 \\  \\  \large \bf \implies \theta =   { \cos}^{ - 1}  \bigg( \dfrac{1}{2} \bigg)  \implies60 ^\circ

So, the value of \theta = 60^\circ

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Answered by omtiwari1817
3

Answer:

60

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