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EXPECTED :- MODS AND MATHS ARYABHATTA​

Answer 1

Answer:

• The required distance between AB is 5√2 cm .

Step-by-step explanation:

• Let the two points be A ( -2 , -3) and B ( 3 ,2).

We have to find the distance between AB

Here, [ x1 = - 2 , x2 = 3 ] & [ y1 = -3 , y2 = 2]

Now, Using Distance Formula:

∴ AB = √[( x2 - x1)² + ( y2 - y1)²]

• AB = √[ {3 - ( -2)}² + {( 2 - ( -3)}²]
• AB = √[ ( 3 + 2)² + ( 2 + 3)²]
• AB = √[ (5)² + (5)²]
• AB = √[ 25 + 25 ]
• AB = √50
• AB = √50 AB = 5√2 cm

Therefore, the required distance between AB is 5√2 cm.

Answer 2

$\huge \underline \mathfrak {Solution:-}$

We have to find out the distance between the two points (-2,-3) and (3,2).

For finding the distance between two points we can use the given formula.

Distance $= \sqrt{ {(x_1 - x_2)}^{2} + {(y_1 - y_2)}^{2} }$

According to question,

$x_1 = - 2 \\ \\ x_2 = 3 \\ \\ y_1 = - 3 \\ \\ y_2 = 2$

Now,

Distance $= \sqrt{ {(x_1 - x_2)}^{2} + {(y_1 - y_2)}^{2} }$

$= \sqrt{ {( - 2 - 3)}^{2} + {( - 3 - 2)}^{2} } \\ \\ = \sqrt{ {( - 5)}^{2} + { (- 5)}^{2} } \\ \\ = \sqrt{ {5}^{2} + {5}^{2} } \\ \\ = \sqrt{ {5}^{2}(1 + 1) } \\ \\ = 5 \sqrt{2} \: units$

So, the distance between the points is 5√2 units.