Question

Question For You

PLEASE ANSWER THIS QUESTION

EXPECTED :- MODS AND MATHS ARYABHATTA​

Answer 1

Answer:

5√2

Step-by-step explanation:

distance between any two points is √((x2-x1)^2+(y2-y1)^2)

=√((3-(-2))^2+(2-(-3))^2)

=√(5)^2+(5)^2

=√50

=5√2

Answer 2

$\huge{ \red{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: QUESTION \: \: \red{ \mid}}}}}}}}$

$\rm{Find \: \: the \: \: distance \: \: between \: \: the \: \: following} \\ \rm{pair \: \: of \: \: points \: \: ( - 2 \: , \: - 3) \: \: and \: \: (3 \:, \: 2) \: .}$

$\huge{ \red{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION\: \: \red{ \mid}}}}}}}}$

$\huge{\underline{ \rm{ \: \:Given \: : \to}}} \: \: \: \\ \\ \rm{The \: \: two \: \: points \: \: are \: \: ( - 2 \:, \: - 3) \: and \: \: (3 \:, \: 2)}$

$\sf{Let,} \: \: \: \: \: \: \sf{ x_1 = - 2} \\ \: \: \: \: \: \: \: \: \: \: \: \sf{ y_1 = - 3} \\ \: \: \: \: \: \: \: \: \: \: \: \sf{ x_2 = 3} \\ \: \: \: \: \: \: \: \: \: \: \: \sf{ y_2 = 2}$

$\huge{ \underline{ \rm{ \: \: We \: \: \: know \: \: \: that \: \: }}}$

$\sf{The \: \: distance \: \: between \: \: two \: \: points \: \: (x_1 \: ,\: y_1) \: \: and} \\ \sf{(x_2 \: ,\: y_2) \: \: is}$

$\boxed{\rm{Distance = \sqrt{(x_2 -x_1) {}^{2} + ( y_2 -y_1) {}^{2} } } \: \: }$

$\rm{\therefore \: \: The \: \: distance \: \: between \: \: the \: \: points\: \: ( - 2 \:, - 3) \: \: and \: \: (3 ,\: 2) } \\ \\ \rm{is\: = \sqrt{(x_2 - x_1) {}^{2} + ( y_2- y_1) {}^{2} } } \\ \\ \: \: \: \: \rm{ = \sqrt{(3 - ( - 2) ){}^{2} + (2 - ( - 3)) {}^{2} } } \\ \\ \: \: \: \: \rm{ = \sqrt{(3 + 2) {}^{2} + (2 + 3) {}^{2} } } \\ \\ \: \: \: \: \rm{ = \sqrt{(5) {}^{2} + (5) {}^{2} } } \\ \\ \: \: \: \: \rm{ = \sqrt{25 + 25} } \\ \\ \: \: \: \: \rm{ = \sqrt{2 \times 25} } \\ \\ \: \: \: \: \rm{ = \sqrt{2 \times (5) {}^{2} } } \\ \\ \: \: \: \: \rm{ = 5 \sqrt{2} }$

$\sf{So} \\ \\ \sf{The \: \: distance \: \: between \: \: the \: \: following} \\ \sf{pair \: \: of \: \: points \: \: \red{ ( - 2 \:, \: - 3)} \: \: and \: \: \red{(3 \:, \: 2) }\: is} \\ \sf{ \underline{ \red{ \: 5 \sqrt{2} \: \: units}\:. }}$