Question from 3D vector .
Find the co-ordinate of the point on the line x-2/1=y+3/2 =z-5/2 at a distance of 3units from the point (2,-3,-5)
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Answer:- [3,-5,-3] or [1,-1,-7]
Step-by-step explanation:
Let , x-2/1= y+3/2 = z+5/2 = L
x= L + 2 , y = 2L-3 , z = 2L-5
From distance formula ,
(L +2 - 2)² + (-2L -3+3) ²+ (2L-5-5)² =9
L² -4L²+L² = 9
9L² = 9
L = +-1
since, putting the value , we get , [3,-5,-3 ] or [1,-1,-7]
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Hope it helps !
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