Question from chapter quadratic polynomial.
If sum and product of zeros of a quadratic polynomial are 1 and -30 respectively.
Then Find that polynomial.
Don't post useless things as in my previous question ¤¤¤¤¤¤¤¤¤¤¤¤¤¤》 ▪Given :- \bf y = [log \{log(logx) \}] {}^{2}y =[log{log(logx)}] 2 ___________________________ ▪To Calculate :- \bf \large \color{magenta}{dy/dx}dy/dx ___________________________ ▪Formulae Used :- \begin{gathered} \bigstar \: \bf \frac{d}{dx} f(x) {}^{2} = 2f(x) \frac{d}{dx} f(x) \\ \\ \bigstar \bf\frac{d}{dx} log(f(x)) = \frac{1}{f(x)} . \frac{d}{dx} f(x)\end{gathered} ★ dx d f(x) 2 =2f(x) dx d f(x) ★ dx d log(f(x))= f(x) 1 . dx d f(x) ___________________________ ▪Solution :- \bf y = [log \{log(logx) \}] {}^{2}y =[log{log(logx)}] 2 Differentiating both side w.r.t x \begin{gathered} \bf\frac{dy}{dx} = \frac{d}{dx} [log \{log(logx) \}] {}^{2} \\ \\ = \sf2[log \{log(logx) \}] .\frac{d}{dx} [log \{log(logx) \}] \\ \\ = \sf 2[log \{log(logx) \}] \times \frac{1}{ \{log(log \: x) \} } \\ \times \sf\frac{ d}{dx} \{log{(log \: x)} \} \\ \\ = \sf 2[log \{log(logx) \}] \times \frac{1}{ \{log(log \: x) \} } \\ \times \sf\frac{1}{log \: x} \times \frac{d}{dx}log \: x \\ \\ = \sf 2[log \{log(logx) \}] \times \frac{1}{ \{log(log \: x) \} } \\ \times \sf\frac{1}{log \: x} \times \frac{1}{x}\\\\ \colorbox{lime}{ \underline{\boxed{\bf \frac{dy}{dx}=\frac{2[log \{log(logx)\}]}{x log \: x.\{log(log \: x)\} }}}} \end{gathered} dx dy = dx d [log{log(logx)}] 2 =2[log{log(logx)}]. dx d [log{log(logx)}] =2[log{log(logx)}] × {log(logx)} 1 × dx d {log(logx)} =2[log{log(logx)}] × {log(logx)} 1 × logx 1 × dx d logx =2[log{log(logx)}] × {log(logx)} 1 × logx 1 × x 1 dx dy = xlogx.{log(logx)} 2[log{log(logx)}] \begin{gathered} \Large \color{purple}\mathfrak{ \text{W}hich \: \: is \: \: the \: \: required }\\ \huge \color{navy} \mathfrak{ \text{ A}nswer.}\end{gathered} Which is the required Answer. ___________________________
Answers
Answer:
Dear students and respected parents, it is to inform you that our vidyalaya is going to organize yoga activities week under the programme of 7th International yoga Day (Digital Yoga Movement), daily from tomorrow i.e 15/06/2021 to 21/06/2021.
In the series of yoga day programmes from tomorrow daily live yoga session will be held through vidyalaya facebook page from 7 A.M to 8 A.M.
All the students and their parents and relatives are requested to attend the yoga session and participate.
The link will be shared at 6:50 A.M tomorrow.
Stufents are further directed to like/comment on the programme.
Answer:
Ambedkar was appointed to an all-European commission in 1925 which was formed to study the constitutional reforms in Birtish India. Name the Commission.