Question

question from Gravitation Class 11​

Answer 1

Answer:

Opt A which is √(2h/g)

Explanation:

As h<<R we will consider the gravity to be 'g' itself

By 2nd equation of motion under uniform acceleration

S = ut + 1/2 at^2

Here, S = h, u = 0 (It is dropped), a = g

So, h = 0.t + 1/2 gt^2

gt^2 = 2h

t^2 = 2h/g

t = √(2h/g)

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