Question from mensuration.
A piece of paper is
in the shape of a sector of a circle whose radius is 12cm and the central angle
of the sector is 120 degree it is rolled to form a cone of the biggest
possible capacity .Find the capacity of the cone.
Answers
Answered by
38
Lateral or slanting height of cone L
= radius of the circle from which the sector is cut
L = 12 cm
Arc length of the 120° sector = 2π * radius * 120°/360° = 8 π cm
Circumference of the base circle of cone = arc length = 8π cm = 2 π R
So, R = radius of the circle of base of cone = 4 cm
Area of base of cone = πR² = 16 π cm²
Altitude or Height of cone = H = √(L² - R²) = √(12² - 4²) = √128 = 8√2 cm
Volume or capacity of Cone = 1/3 * base area * Altitude
= 1/3 * 16 π * 8 √2 = 128√2π / 3 cm³
= radius of the circle from which the sector is cut
L = 12 cm
Arc length of the 120° sector = 2π * radius * 120°/360° = 8 π cm
Circumference of the base circle of cone = arc length = 8π cm = 2 π R
So, R = radius of the circle of base of cone = 4 cm
Area of base of cone = πR² = 16 π cm²
Altitude or Height of cone = H = √(L² - R²) = √(12² - 4²) = √128 = 8√2 cm
Volume or capacity of Cone = 1/3 * base area * Altitude
= 1/3 * 16 π * 8 √2 = 128√2π / 3 cm³
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0
Answer:
10pi/13
Step-by-step explanation:
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