Question

Question from Molarity

Answer 1

9.8% w/w means 9.8 g H2SO4 is present in 100 g of solution

molality = moles of solute/weight of solvent

weight of solvent = wt of solution- wt of solute
= 100-9.8
= 91.2

moles of solute = 9.8/98 = 0.1

molality = 0.1/91.2
= 0.001

Answer 2

${\sf{\green{\underline{\huge{molarity\: of \:9.8 ℅ \:solution\: of \:H2SO4}}}}}$

$<b><i><u>$

Molar mass of H2SO4 = 98g/mol = Mm

D =density = 1.84g/cc

W/w = 98%

V = 1dm3 = 1L = 1000ml = 1000cc

Mass of solution = V x D

M = 1000 x 1.84 = 1840g per 1000cc

Using w/w, 98% of 1840g = H2SO4

= (98/100) x 1840 = 1803.2g = m

Nos of moles = m/Mm = 1803.2/98 = 18.4moles per 1000cc

Thus, molarity = 18.4M (18.4mol/dm3)