Physics, asked by aravind9490, 10 hours ago

Question from ray optics
Question from ray optics A fish is near the centre of a spherical water filled ( = 4/3) fish bowl. A child stands in air at a distance 2R (R is the radius of curvature of the sphere) from the centre ofthe bowl. At what distance from the centre would the child nose appear to the fish situated at the centre :

Answers

Answered by visvappriyasasikumar
0

Explanation:

Correct option is

C

3R

We use the formula for different refractive indices,

v

1

3u

4

=

R

3

4

+1

Substituting, u=2R

v

1

3R

2

=

3R

−1

This gives the value of v as 3R

Answered by mumshitaa
1

Explanation:

Refraction at the spherical refracting surface from rarer to denser medium can be given by,

μ2v−μ1u=μ2−μ1Rμ2v−μ1u=μ2−μ1R

⇒43v−1−R=43−1R⇒43v−1−R=43−1R

⇒43v+1R=13R⇒43v+1R=13R

⇒43v=−23R⇒43v=−23R

⇒v=−4R2=−2R⇒v=−4R2=−2R

The value is, v=2Rv=2R

Hence the right answer is option (B)⇒2R

(B)⇒2R

.

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