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Two thin lenses of focal lengths +10 cm and -5 cm are kept in contact. What is the (i) focal length and (ii) power of the combination??
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Solution:-
Here,
f1 = +10cm = 0.10m
f2 = -5cm = - 0.05m
(i) 1/f = (1/f1) + (1/f2)
= (1/0.10) + (1/-0.05)
= -10
f = -1/10 m = -10cm.
(ii) P = P1 + P2
= (1/f1) + (1/f2) = -10D or dioptre
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Anonymous:
Nice answer Utkarsh ji!❤
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