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@Zia Dilliwali
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✍ 189 cm³/s
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EXPLANATION —
↪Actually welcome to the concept of Fluid Mechanics
↪Basically we will use Bernoullis Equation and Equation of Continuity
Let the velocity at x = vx and at y = vy
By the equation of continuity vx/vy = 3/1.5 = 2
Now By Bernoullis
Px + 1/2pvx² = Py + 1/2 pvy²
Px - Py = 1/2 p(2vy)² — 1/2pvy² = 3/2 pvy²
600 N/m² = 3/2 (1000 kg/m³) vx²
vx = 0.63 m/s
Therefore the rate of flow = (3cm²)(0.63 m/s). = 189 cm³/s
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Answer :
Rate of flow of water through the tube = 1.89 × 10^-4 m³/s.
Explanation :
Let velocity at x & y are Vx & Vy respectively.
By equation of continuity,
Vy/Vx = 3/1.5 = 2
By Bernoulli's equation,
Px + (1/2)ρ(Vx)² = Py + (1/2)ρ(Vy)²
Px − Py = (1/2)ρ(2Vx)² − (1/2)ρ(Vx)²
= (3/2)ρ(Vx)²
⇒600 = 32(1000)(Vx)²
=> Vx = 0.63 m/s
∴ Rate of flow = (3 × 10^-4) × (0.63)
⇒1.89 × 10^-4 m³/s