Question

Question (g) please answer the question

Answer 1

Given,

$\bold{x=y=2b}$

Given equation,

$\bold{\frac{x}{a}+\frac{y}{b}=1}$

Applying the value of y(= 2b) to the equation,

$\implies\bold{\frac{x}{a}+\frac{2b}{b}=1}$

$\implies\bold{\frac{x}{a}+2=1}$

$\implies\bold{\frac{x}{a}=1-2}$

$\implies\bold{\frac{x}{a}=-1}$

Given, x = 3

$\implies\bold{\frac{3}{a}=-1}$

$\implies\bold{a=\frac{3}{-1}}$

$\implies\bold{a=-3}$

$\boxed{\bold{\therefore a=-3}}$

Answer 2

$\large \mathbb{GIVEN:-}$

$\bf \bullet \quad \dfrac{x}{a} + \dfrac{y}{b} = 1$

$\bf \bullet \quad x = y = 2b=3$

$\large \mathcal{TO \ FIND:-}$

The value of $a$

$\large \mathbb{SOLUTION:-}$

x = y = 2b = 3,

then

• x = 3
• y = 3
• 2b = 3/2 or 1.5

Substituting the values,

$\bf \implies \dfrac{3}{a} + \dfrac{3}{1.5} = 1$

$\bf \implies \dfrac{3}{a} + 2 = 1$

$\bf \implies \dfrac{3}{a} = 1- 2$

$\bf \implies \dfrac{3}{a} = -1$

$\bf \implies 3 = -1 \times a$

$\bf \implies 3 = -a$

$\bf \implies -3 = a$

$\boxed{\bf a = -3}$