question: Geometry ( one )
congruence of triangle.
please help me!!!
give the answer step-by-step
AB and CD two equal and parallel straight lines. AD and BC when joined meet at O. prove that AO = OD
as congruence
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answer is right. I hope you understand.
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Refer to the attachment for the diagram.
Consider Δ AOB and Δ COD
⇒ ∠ BAO = ∠ ODC ( A ) : Alternate Angles
⇒ ∠ AOB = ∠ COD ( A ) : Vertically Opposite Angles
⇒ ∠ OBA = ∠ OCD ( A ) : Alternate Angles
Therefore by AAA congruence rule, we get
Δ AOB ≅ Δ COD
By CPCT, we can say that OA = OD, OB = OC
Hence Proved !!
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