Math, asked by 5290321chiru, 29 days ago

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Answered by shlokaraod
3

Answer:

In 1st bit c) 912, 4194, 5214

D) 130

In 2nd bit 1647, 1161

Explanation:

For 6 divisibility which should check for both 2 & 3

For 2, units place digit should be even no

For 3, the sum of the digits should be a multiple of 3

For 10, the last digit should be 0

For 9, the sum of the digits should be a multiple of 9

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