Question

Question given in the atttachment chapter :- Thermodynamics​

Answer 1

Answer:

Let the amount of ice is m gm

According to the principle of calori meter

Heat taken by ice=heat given by water

20×2.1×m+(m-20)334

50×4.2×40

376m=8400+6680

m=40.1

Explanation:

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Answer 2

Answer:

Option (a) 40g

Explanation:

Let amount of ice be 'x' gm

according to the principle of calorimeter,

heat lost by water = heat gained by ice

Here, heat lost by water , ∆Q = ms∆T

Substituting the given values , we get

∆Q = 50× 42× 40

Heat gained by

∆Q = x S(ice) ∆T + ( x - 20) L

• = x × 2.1 × 20 + (x -20( × 334

• = 20x × 2.1 + 334x - 6680

• → 20x × 2.1 + 334x -6680 = 50 × 42 ×40

• 42x + 334x -6680 = 8400

• 376x = 15080

• or, x = 40.10g

x = 40g Answer