Math, asked by UtsavPlayz, 1 year ago

QUESTION ==>

The Sum of Diameters of two Circles is 2.8 m and the difference of their Circumferences is 0.88 m. Find the Radii of the two Circles in cm.

Answers

Answered by Anonymous
33
\underline\bold{\huge{ANSWER \: :}}

Let the diameter of first circle be D1

Let the diameter of second circle be D2

Similarly let the radius of first circle be r1 and that of the second circle be r2.

Given, D1+ D2 = 2.8

=> 2r1 + 2r2 = 2.8

=> 2 (r1 + r2) = 2.8

=> r1 + r2 = (2.8/2) m = 1.4 m ......... (I)

Also, 2πr1 - 2πr2 = 0.88

=> 2 π (r1 - r2) = 0.88

=> r1 - r2 = (0.88)/{2×(22/7)}

=> r1 - r2 = (0.88)/(44/7)

=> r1 - r2 = 0.14 m .......... (II)

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Now, adding two equations, we get :

r1 + r2 + r1 - r2 = 1.4 + 0.14

=> 2r1 = 1.54

=> r1 = 0.77 m or 77 cm
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If r1 = 0.77 m, then :

r1 + r2 = 1.4

=> 0.77 + r2 = 1.4

=> r2 = 1.4 - 0.77

=> r2 = 0.63 m or 63 cm.
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Hence, the required answer is the radii of two circles (in cm) are 77 cm and 63 cm.
Answered by SSSSSSSSSSSSS89
16
❤ HERE IS YOUR ANSWER DEAR ❤
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Say, the diameter of first circle be D1 and similarly the diameter of second circle be D2
______________________________

Accordingly, let the radius of first circle be r1 and that of the second circle be r2.
______________________________

Given, D1+ D2 = 2.8 

=> 2r1 + 2r2 = 2.8

=> 2 (r1 + r2) = 2.8

=> r1 + r2 = (2.8/2) m = 1.4 m ......... (I) 

______________________________

Also we can write,

2πr1 - 2πr2 = 0.88

=> 2 π (r1 - r2) = 0.88

=> r1 - r2 = (0.88)/{2×(22/7)} 

=> r1 - r2 = (0.88)/(44/7)

=> r1 - r2 = 0.14 m .......... (II) 

______________________________

Now, adding two equations, we get :

r1 + r2 + r1 - r2 = 1.4 + 0.14

=> 2r1 = 1.54

=> r1 = 0.77 m or 77 cm
______________________________

If r1 = 0.77 m, then :

r1 + r2 = 1.4

=> 0.77 + r2 = 1.4

=> r2 = 1.4 - 0.77

=> r2 = 0.63 m or 63 cm. 
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HENCE, YOUR PROBLEM IS SOLVED

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AdorableAstronaut: xD
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