QUESTION ==>
The Sum of Diameters of two Circles is 2.8 m and the difference of their Circumferences is 0.88 m. Find the Radii of the two Circles in cm.
Answers
Answered by
33
Let the diameter of first circle be D1
Let the diameter of second circle be D2
Similarly let the radius of first circle be r1 and that of the second circle be r2.
Given, D1+ D2 = 2.8
=> 2r1 + 2r2 = 2.8
=> 2 (r1 + r2) = 2.8
=> r1 + r2 = (2.8/2) m = 1.4 m ......... (I)
Also, 2πr1 - 2πr2 = 0.88
=> 2 π (r1 - r2) = 0.88
=> r1 - r2 = (0.88)/{2×(22/7)}
=> r1 - r2 = (0.88)/(44/7)
=> r1 - r2 = 0.14 m .......... (II)
______________________________
Now, adding two equations, we get :
r1 + r2 + r1 - r2 = 1.4 + 0.14
=> 2r1 = 1.54
=> r1 = 0.77 m or 77 cm
______________________________
If r1 = 0.77 m, then :
r1 + r2 = 1.4
=> 0.77 + r2 = 1.4
=> r2 = 1.4 - 0.77
=> r2 = 0.63 m or 63 cm.
______________________________
Hence, the required answer is the radii of two circles (in cm) are 77 cm and 63 cm.
Answered by
16
❤ HERE IS YOUR ANSWER DEAR ❤
______________________________
Say, the diameter of first circle be D1 and similarly the diameter of second circle be D2
______________________________
Accordingly, let the radius of first circle be r1 and that of the second circle be r2.
______________________________
Given, D1+ D2 = 2.8
=> 2r1 + 2r2 = 2.8
=> 2 (r1 + r2) = 2.8
=> r1 + r2 = (2.8/2) m = 1.4 m ......... (I)
______________________________
Also we can write,
2πr1 - 2πr2 = 0.88
=> 2 π (r1 - r2) = 0.88
=> r1 - r2 = (0.88)/{2×(22/7)}
=> r1 - r2 = (0.88)/(44/7)
=> r1 - r2 = 0.14 m .......... (II)
______________________________
Now, adding two equations, we get :
r1 + r2 + r1 - r2 = 1.4 + 0.14
=> 2r1 = 1.54
=> r1 = 0.77 m or 77 cm
______________________________
If r1 = 0.77 m, then :
r1 + r2 = 1.4
=> 0.77 + r2 = 1.4
=> r2 = 1.4 - 0.77
=> r2 = 0.63 m or 63 cm.
______________________________
HENCE, YOUR PROBLEM IS SOLVED
______________________________
______________________________
Say, the diameter of first circle be D1 and similarly the diameter of second circle be D2
______________________________
Accordingly, let the radius of first circle be r1 and that of the second circle be r2.
______________________________
Given, D1+ D2 = 2.8
=> 2r1 + 2r2 = 2.8
=> 2 (r1 + r2) = 2.8
=> r1 + r2 = (2.8/2) m = 1.4 m ......... (I)
______________________________
Also we can write,
2πr1 - 2πr2 = 0.88
=> 2 π (r1 - r2) = 0.88
=> r1 - r2 = (0.88)/{2×(22/7)}
=> r1 - r2 = (0.88)/(44/7)
=> r1 - r2 = 0.14 m .......... (II)
______________________________
Now, adding two equations, we get :
r1 + r2 + r1 - r2 = 1.4 + 0.14
=> 2r1 = 1.54
=> r1 = 0.77 m or 77 cm
______________________________
If r1 = 0.77 m, then :
r1 + r2 = 1.4
=> 0.77 + r2 = 1.4
=> r2 = 1.4 - 0.77
=> r2 = 0.63 m or 63 cm.
______________________________
HENCE, YOUR PROBLEM IS SOLVED
______________________________
AdorableAstronaut:
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