Question => There is a tank in the cylindrical form whose radius is 2.1 cm and height is 4.5 CM. find how much still was actually used if 1/12 of the Steel actually used was wasted in the making tank
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Given:h=4.5cm,r=2.1m
Total surface area of tank=2πr(r+h)
= 2×7/22×2.1×(2.1+4.5)
=2×7/22×2.1×6.6=87.12m²
Let amount of steel used in making the tank x
Steel wasted=x/12
Given that:Amount of steel required−Amount of steel wasted=TSA of tank.
= x−12/x=87.12
= 11x/12 =87.12
x=12/11×87.12=95.04m²
Therefore
95.04m² steel was used in actual while making such a tank.
hope it helps you
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Answer:
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Given:h=4.5cm,r=2.1m
Total surface area of tank=2πr(r+h)
= 2×7/22×2.1×(2.1+4.5)
=2×7/22×2.1×6.6=87.12m²
Let amount of steel used in making the tank x
Steel wasted=x/12
Given that:Amount of steel required−Amount of steel wasted=TSA of tank.
= x−12/x=87.12
= 11x/12 =87.12
x=12/11×87.12=95.04m²
Therefore
95.04m² steel was used in actual while making such a tank.
hope it helps you
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