Question

Question... Hope, I would get it’s solution soon

Answer 1

Answer:

f(x)=x3−12x2+19x−28

Zeroes are in AP.

Let the zeroes be of the form

a-d,a,a+d

sum of roots = 12

3a=12

a = 4

product of roots =−ad

a(a2−d2)=(−28)

a3−ad2=28

(4)3−4d2=28

64−4d2=28

4d2=36

d=±3

Zeroes are 1,4,7 or 7,4,1