Physics, asked by Anonymous, 2 months ago

Question How much positive and negative charge is there in a cup of water?
Questions If 10^9 electrons move out of a body to another body every second ,how much time is required to get a total charge of 1 Coulomb on the other body?​

Answers

Answered by Anonymous
5

\huge \bold \pink {\mathbb {answer}}

Let us consider that one cup of has 250 ml of water

Density of water is 1 g/cc in cgs system

Therefore the mass of one cup of water =250 g

Molecular weight of water =18 g

Number of moles of water in 250gram=

18

250

=13.888moles

We know that one mole=6.02×10

23

molecules.

The number of molecules in one cup of water=13.888×6.02×10

23

=8.36×10

24

molecules.

1 molecule of water=2hydrogen(2 protons)+1oxygen(8 protons)

Total protons in one water molecule=10=Total number of electrons.

Total positive and negative charge has the same magnitude.

We know charge of proton=1.6×10

−19

C

Total positive charge in 250g of water in cup=10×8.36×10

24

×1.6×10

−19

=1.338×10

7

C

So i one cup of water (250ml) there are 1.338×10

7

C positive charge and −1.338×10

7

C negative charge

Totally they will be neutral.

Answered by Anonymous
1

Answer:

Let us consider that one cup of has 250 ml of water

Density of water is 1 g/cc in cgs system

Therefore the mass of one cup of water =250 g

Molecular weight of water =18 g

Number of moles of water in 250gram=

18

250

=13.888moles

We know that one mole=6.02×10

23

molecules.

The number of molecules in one cup of water=13.888×6.02×10

23

=8.36×10

24

molecules.

1 molecule of water=2hydrogen(2 protons)+1oxygen(8 protons)

Total protons in one water molecule=10=Total number of electrons.

Total positive and negative charge has the same magnitude.

We know charge of proton=1.6×10

−19

C

Total positive charge in 250g of water in cup=10×8.36×10

24

×1.6×10

−19

=1.338×10

7

C

So i one cup of water (250ml) there are 1.338×10

7

C positive charge and −1.338×10

7

C negative charge

Totally they will be neutral.

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