Chemistry, asked by Rajput2stars, 9 months ago

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IᏁ ᏆhᎬ ᏢᏒᎬsᎬᏁᏟᎬ Ꮎf CN, (Ꭺ sᏆᏒᎾᏁᎶ ᏞᎥᎶᎪᏁᎠ) ᏆhᎬ 3Ꭰ ᎬᏞᎬᏟᏆᏒᎾᏁs ᏢᎪᎥᏒ uᏢ ᏞᎬᎪᏉᎥᏁᎶ ᎾᏁᏞᎽ ᎾᏁᎬ uᏁᏢᎪᎥᏒᎬᎠ ᎬᏞᎬᏟᏆᏒᎾᏁ. ThᎬ hᎽbᏒᎥᎠᎥsᎪᏆᎥᎾᏁ Ꭵs Ꭰ² sᏢ³ fᎾᏒmᎥᏁᎶ ᎥᏁᏁᎬᏒ ᎾᏒbᎥᏆᎪᏞ ᏟᎾmᏢᏞᎬx. IᏁ ᏆhᎬ ᏢᎬᏒsᎬᏁᏟᎬ Ꮎf H2O, (Ꭺ ᎳᎬᎪᏦ ᏞᎥᎶᎪᏁᎠ), 3Ꭰ ᎬᏞᎬᏟᏆᏒᎾᏁs ᎠᎾ ᏁᎾᏆ ᏢᎪᎥᏒ uᏢ. ThᎬ hᎽbᏒᎥᎠᎥsᎪᏆᎥᎾᏁ Ꭵs sᏢ³ Ꭰ³ fᎾᏒmᎥᏁᎶ ᎪᏁ ᎾuᏆᎬᏒ ᏟᎾmᏢᏞᎬx ᏟᎾᏁᏆᎪᎥᏁᎥᏁᎶ fᎥᏉᎬ uᏁᏢᎪᎥᏒᎬᎠ ᎬᏞᎬᏟᏆᏒᎾᏁs, ᎥᏆ Ꭵs sᏆᏒᎾᏁᎶᏞᎽ ᏢᎪᏒᎪmᎪᎶᏁᎬᏆᎥᏟ.​

Answers

Answered by aman7913
2

HERE YOUR ANSWER:

[Fe(H2O)6]^-2 is strongly paramagnetic where [Fe(CN)6]^-3 is weakly paramagnetic.

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hope it helps you

Answered by Anonymous
24

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IᏁ ᏆhᎬ ᏢᏒᎬsᎬᏁᏟᎬ Ꮎf CN, (Ꭺ sᏆᏒᎾᏁᎶ ᏞᎥᎶᎪᏁᎠ) ᏆhᎬ 3Ꭰ ᎬᏞᎬᏟᏆᏒᎾᏁs ᏢᎪᎥᏒ uᏢ ᏞᎬᎪᏉᎥᏁᎶ ᎾᏁᏞᎽ ᎾᏁᎬ uᏁᏢᎪᎥᏒᎬᎠ ᎬᏞᎬᏟᏆᏒᎾᏁ. ThᎬ hᎽbᏒᎥᎠᎥsᎪᏆᎥᎾᏁ Ꭵs Ꭰ² sᏢ³ fᎾᏒmᎥᏁᎶ ᎥᏁᏁᎬᏒ ᎾᏒbᎥᏆᎪᏞ ᏟᎾmᏢᏞᎬx. IᏁ ᏆhᎬ ᏢᎬᏒsᎬᏁᏟᎬ Ꮎf H2O, (Ꭺ ᎳᎬᎪᏦ ᏞᎥᎶᎪᏁᎠ), 3Ꭰ ᎬᏞᎬᏟᏆᏒᎾᏁs ᎠᎾ ᏁᎾᏆ ᏢᎪᎥᏒ uᏢ. ThᎬ hᎽbᏒᎥᎠᎥsᎪᏆᎥᎾᏁ Ꭵs sᏢ³ Ꭰ³ fᎾᏒmᎥᏁᎶ ᎪᏁ ᎾuᏆᎬᏒ ᏟᎾmᏢᏞᎬx ᏟᎾᏁᏆᎪᎥᏁᎥᏁᎶ fᎥᏉᎬ uᏁᏢᎪᎥᏒᎬᎠ ᎬᏞᎬᏟᏆᏒᎾᏁs, ᎥᏆ Ꭵs sᏆᏒᎾᏁᎶᏞᎽ ᏢᎪᏒᎪmᎪᎶᏁᎬᏆᎥᏟ.

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Through the above information we came to know that

 {Fe(H2O)6}^{ - 2} is strong paramagnet

and Fe(CN)-³ is weak paramagnet.

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