Question

⊕QUESTION⊕
i hate maths !!!!! jus solve the below question
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CLASS 11
PERMUTATIONS AND COMBINATIONS
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How many integers between 100 and 10000 have no digits other than 4, 5 and 6?

Answer 1

The integer in between 1000 to 10000 must be 4 digits.

then no of integer in between 1000 to 10000 having digit 4,5,6 is = 3*3*3*3 = 81.

Answer 2

Answer:

Step-by-step explanation:

Any number between 1,000 and 10,000 is of 4 digits. The unit’s place can be filled up by 4,5 or 6, that is, in 3 ways.

Similarly, the ten’s place can be filled up by 4 or 5 or 6, that is in 3 ways. The hundred’s place can be filled up by 4, 5 or 6, that is in 3 ways and the thousand’s place can.be filled up by 4 or 5 or 6, that is, in 3 ways.

Hence the required numbers = 3 x 3 x 3 x 3 = 81