Question

QUESTION:If 1st and 5th terms of a G.P are 512 and 32 respectively,then its 2nd terms is?

Answer 1

Answer:

x2= 392

Step-by-step explanation:

x1= 512

x5=32

(5-1)d=32-512

4d= -480

d= -120

x2= x1+d

= 512+-120

x2= 392

Answer 2

Answer: second term is 256

Step-by-step explanation:

Let the first term of the GP be “a”, and the common ratio be “r”

According to the question, a = 512

To find the “n”th term of a GP we use the formula

$a*r^{n-1} = a_{n}$ where n= “n”th term

=> fifth term = $a*r^{5-1} = a*r^{4} = 36$

=> $512*r^{4} = 32\\\\=> r^{4} = \frac{32}{512}\\\\=> r = \sqrt[4]{\frac{1}{16}}\\\\=> r = \frac{1}{2}$

Therefore, The second term would be

$a * r^{2-1} \\=> a * r^{1}\\=> a * r\\=> 512 * \frac{1}{2}\\=> 256$

Therefore, the second term is 256

Please brainlist my answer, if helpful!